geopandas.GeoSeries.intersects¶
- GeoSeries.intersects(other, align=True)¶
Returns a
Series
ofdtype('bool')
with valueTrue
for each aligned geometry that intersects other.An object is said to intersect other if its boundary and interior intersects in any way with those of the other.
The operation works on a 1-to-1 row-wise manner:
- Parameters
- otherGeoSeries or geometric object
The GeoSeries (elementwise) or geometric object to test if is intersected.
- alignbool (default True)
If True, automatically aligns GeoSeries based on their indices. If False, the order of elements is preserved.
- Returns
- Series (bool)
Notes
This method works in a row-wise manner. It does not check if an element of one GeoSeries
crosses
any element of the other one.Examples
>>> from shapely.geometry import Polygon, LineString, Point >>> s = geopandas.GeoSeries( ... [ ... Polygon([(0, 0), (2, 2), (0, 2)]), ... LineString([(0, 0), (2, 2)]), ... LineString([(2, 0), (0, 2)]), ... Point(0, 1), ... ], ... ) >>> s2 = geopandas.GeoSeries( ... [ ... LineString([(1, 0), (1, 3)]), ... LineString([(2, 0), (0, 2)]), ... Point(1, 1), ... Point(0, 1), ... ], ... index=range(1, 5), ... )
>>> s 0 POLYGON ((0.00000 0.00000, 2.00000 2.00000, 0.... 1 LINESTRING (0.00000 0.00000, 2.00000 2.00000) 2 LINESTRING (2.00000 0.00000, 0.00000 2.00000) 3 POINT (0.00000 1.00000) dtype: geometry
>>> s2 1 LINESTRING (1.00000 0.00000, 1.00000 3.00000) 2 LINESTRING (2.00000 0.00000, 0.00000 2.00000) 3 POINT (1.00000 1.00000) 4 POINT (0.00000 1.00000) dtype: geometry
We can check if each geometry of GeoSeries crosses a single geometry:
>>> line = LineString([(-1, 1), (3, 1)]) >>> s.intersects(line) 0 True 1 True 2 True 3 True dtype: bool
We can also check two GeoSeries against each other, row by row. The GeoSeries above have different indices. We can either align both GeoSeries based on index values and compare elements with the same index using
align=True
or ignore index and compare elements based on their matching order usingalign=False
:>>> s.intersects(s2, align=True) 0 False 1 True 2 True 3 False 4 False dtype: bool
>>> s.intersects(s2, align=False) 0 True 1 True 2 True 3 True dtype: bool